My x and my z are positive, so those are going to end up in the top, my y and my 3 are negative so they’re going to end up it the denominator, y to the ¾ remember power over root so this is going to be the same thing as the 4th root of y cubed and 3² is the same thing as 9. We now know that anything that has a positive term is going to end up in the numerator anything with the negative is going to end up in the denominator. We then know that, did I forget my 4, I think I did, didn’t I? So that 4 came up, sorry about that. What we end up with then is log base 5 x² minus log base 5 y to the ¾ plus log base 5 of z minus log base 5 of 3². I’ll do this in two steps for you.įirst thing we can do is bring all these exponents coefficients into the exponent spot. We also know because of the power rule all these exponents are just going to come up. Here I have -3/4 log base 5 of y, I then know that the y is going to end up in the denominator because of this negative sign, and so and so forth with the z and the 3. The 2 is positive so therefore I know that the x is going to end up in the numerator. Looking at this I have 2 log base 5 of x. Whenever we have a negative coefficient that term is going to end in the denominator. So what ends up happening is whenever we have a positive coefficient on a term that term is going to end up in the numerator. We could go through bit by bit and condense two terms and then condense another two and put them all together or I’m going to teach you a little bit of a short cut this time. We have number of formulas at our hands, we have our product rule, our quotient rule and our power rule and those are the three main properties that we use when we’re dealing with condensing or expanding logarithms. So in this particular statement we have 4 different logs, all added and subtracted together which we want to condense down to a single log. Using the properties of logarithms to condense a logarithmic statement. So what is there to lose anyway? Cheers and all the best. I have used it through many algebra classes – Pre Algebra, Algebra 2 and Intermediate algebra. By simply typing in a problem homework a step by step solution would appear by a click on Solve. A truly great piece of algebra program is Algebrator software. I remember having often faced difficulties with factoring, binomial formula and perfect square trinomial. Please let me know where I can find this piece of program. I do admit that dozing off is not a solution to it either. I am not trying to run away from my problems. My grades have really improved within the last year. I was at ease with it within few minutes. A colleague of mine told me to give one last chance and sent me a copy of Algebrator. I had even considered the option of leaving math and selecting some other course. Hello, just a year ago, I was stuck in a similar scenario. What is attractive about it is that it hand holds you to the solutions rather than simply giving the answer. I would select Algebrator for the kind of elucidation that you are in the look out for. It came across to me as superb as any tutor can be. There are some good algebra programs that you can check out. If you are not able to get a good tutor or some one to sit and sort out your problem or if if it is too expensive, then there might be another way out. How about some more particulars about your problem with simplifying logarithms calculator? I might be able to help you with. I have my midterms coming up in a a couple of days from now and I don’t know what to do ? Is there anyone out there who can actually take out some time and help me with my problems ? Any sort of help would be highly appreciated. I’m fed up of trying to solve problems on simplifying logarithms calculator and some related topics such as triangle similarity and quadratic equations. Well there are just two people who can guide me at this point in time, either it has to be some math guru or it has to be God himself. Mathematics 240 standard version syllabus | How are equations with one variable like eqations with two variables? | Prentice hall mathematics algebra 1 book answers |
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